add 3 books tab

Author: 2xiao

.github/workflows/deploy.yml

@@ -69,6 +69,9 @@ jobs:
           cp -r src/plan ./dist/
           cp -r src/tag ./dist/
           cp -r src/problem ./dist/
+          cp -r src/offer ./dist/
+          cp -r src/offer2 ./dist/
+          cp -r src/interview ./dist/
           cp -r src/image ./dist/
 
       - name: push to main

README.md

@@ -18,8 +18,9 @@
 ## 算法题解
 
 - [LeetCode 题解](./src/problem/README.md)
-- [剑指 Offer](./src/plan/offer_list.md)
-- [剑指 Offer II](./src/plan/offer2_list.md)
+- [剑指 Offer](./src/offer/README.md)
+- [剑指 Offer II](./src/offer2/README.md)
+- [程序员面试金典](./src/interview/README.md)
 
 ## 专项突破
 

assets/origins/interview_list.md

@@ -0,0 +1,17 @@
+---
+title: '目录'
+headerDepth: 0
+---
+
+## 程序员面试金典
+
+###### i_01.01、i_01.02、i_01.03、i_01.04、i_01.05、i_01.06、i_01.07、i_01.08、i_01.09、i_02.01、i_02.02、i_02.03、i_02.04、i_02.05、i_02.06、i_02.07、i_02.08、i_03.01、i_03.02、i_03.03、i_03.04、i_03.05、i_03.06、i_04.01、i_04.02、i_04.03、i_04.04、i_04.05、i_04.06、i_04.08、i_04.09、i_04.10、i_04.12、i_05.01、i_05.02、i_05.03、i_05.04、i_05.06、i_05.07、i_05.08、i_08.01、i_08.02、i_08.03、i_08.04、i_08.05、i_08.06、i_08.07、i_08.08、i_08.09、i_08.10、i_08.11、i_08.12、i_08.13、i_08.14、i_10.01、i_10.02、i_10.03、i_10.05、i_10.09、i_10.10、i_10.11、i_16.01、i_16.02、i_16.03、i_16.04、i_16.05、i_16.06、i_16.07、i_16.08、i_16.09、i_16.10、i_16.11、i_16.13、i_16.14、i_16.15、i_16.16、i_16.17、i_16.18、i_16.19、i_16.20、i_16.21、i_16.22、i_16.24、i_16.25、i_16.26、i_17.01、i_17.04、i_17.05、i_17.06、i_17.07、i_17.08、i_17.09、i_17.10、i_17.11、i_17.12、i_17.13、i_17.14、i_17.15、i_17.16、i_17.17、i_17.18、i_17.19、i_17.20、i_17.21、i_17.22、i_17.23、i_17.24、i_17.25、i_17.26
+
+<style>
+table th:first-of-type { width: 20%; }
+table th:nth-of-type(2) { width: 30%; }
+table th:nth-of-type(3) { width: 10%; }
+table th:nth-of-type(4) { width: 30%; }
+table th:nth-of-type(5) { width: 10%; }
+
+</style>

assets/origins/offer2_list.md

@@ -1,9 +1,9 @@
 ---
-title: '剑指 Offer II'
+title: '目录'
 headerDepth: 0
 ---
 
-![](../image/plan-8.png =500x)
+## 剑指 Offer II
 
 ###### jz_offer_II_001、jz_offer_II_002、jz_offer_II_003、jz_offer_II_004、jz_offer_II_005、jz_offer_II_006、jz_offer_II_007、jz_offer_II_008、jz_offer_II_009、jz_offer_II_010、jz_offer_II_011、jz_offer_II_012、jz_offer_II_013、jz_offer_II_014、jz_offer_II_015、jz_offer_II_016、jz_offer_II_017、jz_offer_II_018、jz_offer_II_019、jz_offer_II_020、jz_offer_II_021、jz_offer_II_022、jz_offer_II_023、jz_offer_II_024、jz_offer_II_025、jz_offer_II_026、jz_offer_II_027、jz_offer_II_028、jz_offer_II_029、jz_offer_II_030、jz_offer_II_031、jz_offer_II_032、jz_offer_II_033、jz_offer_II_034、jz_offer_II_035、jz_offer_II_036、jz_offer_II_037、jz_offer_II_038、jz_offer_II_039、jz_offer_II_040、jz_offer_II_041、jz_offer_II_042、jz_offer_II_043、jz_offer_II_044、jz_offer_II_045、jz_offer_II_046、jz_offer_II_047、jz_offer_II_048、jz_offer_II_049、jz_offer_II_050、jz_offer_II_051、jz_offer_II_052、jz_offer_II_053、jz_offer_II_054、jz_offer_II_055、jz_offer_II_056、jz_offer_II_057、jz_offer_II_058、jz_offer_II_059、jz_offer_II_060、jz_offer_II_061、jz_offer_II_062、jz_offer_II_063、jz_offer_II_064、jz_offer_II_065、jz_offer_II_066、jz_offer_II_067、jz_offer_II_068、jz_offer_II_069、jz_offer_II_070、jz_offer_II_071、jz_offer_II_072、jz_offer_II_073、jz_offer_II_074、jz_offer_II_075、jz_offer_II_076、jz_offer_II_077、jz_offer_II_078、jz_offer_II_079、jz_offer_II_080、jz_offer_II_081、jz_offer_II_082、jz_offer_II_083、jz_offer_II_084、jz_offer_II_085、jz_offer_II_086、jz_offer_II_087、jz_offer_II_088、jz_offer_II_089、jz_offer_II_090、jz_offer_II_091、jz_offer_II_092、jz_offer_II_093、jz_offer_II_094、jz_offer_II_095、jz_offer_II_096、jz_offer_II_097、jz_offer_II_098、jz_offer_II_099、jz_offer_II_100、jz_offer_II_101、jz_offer_II_102、jz_offer_II_103、jz_offer_II_104、jz_offer_II_105、jz_offer_II_106、jz_offer_II_107、jz_offer_II_108、jz_offer_II_109、jz_offer_II_110、jz_offer_II_111、jz_offer_II_112、jz_offer_II_113、jz_offer_II_114、jz_offer_II_115、jz_offer_II_116、jz_offer_II_117、jz_offer_II_118、jz_offer_II_119
 

assets/origins/offer_list.md

@@ -1,9 +1,9 @@
 ---
-title: '剑指 Offer'
+title: '目录'
 headerDepth: 0
 ---
 
-![](../image/plan-7.png =500x)
+## 剑指 Offer
 
 ###### jz_offer_03_1、jz_offer_04_1、jz_offer_05_1、jz_offer_06_1、jz_offer_07_1、jz_offer_09_1、jz_offer_10_1、jz_offer_10_2、jz_offer_11_1、jz_offer_12_1、jz_offer_13_1、jz_offer_14_1、jz_offer_14_2、jz_offer_15_1、jz_offer_16_1、jz_offer_17_1、jz_offer_18_1、jz_offer_19_1、jz_offer_20_1、jz_offer_21_1、jz_offer_22_1、jz_offer_24_1、jz_offer_25_1、jz_offer_26_1、jz_offer_27_1、jz_offer_28_1、jz_offer_29_1、jz_offer_30_1、jz_offer_31_1、jz_offer_32_1、jz_offer_32_2、jz_offer_32_3、jz_offer_33_1、jz_offer_34_1、jz_offer_35_1、jz_offer_36_1、jz_offer_37_1、jz_offer_38_1、jz_offer_39_1、jz_offer_40_1、jz_offer_41_1、jz_offer_42_1、jz_offer_43_1、jz_offer_44_1、jz_offer_45_1、jz_offer_46_1、jz_offer_47_1、jz_offer_48_1、jz_offer_49_1、jz_offer_50_1、jz_offer_51_1、jz_offer_52_1、jz_offer_53_1、jz_offer_53_2、jz_offer_54_1、jz_offer_55_1、jz_offer_55_2、jz_offer_56_1、jz_offer_56_2、jz_offer_57_1、jz_offer_57_2、jz_offer_58_1、jz_offer_58_2、jz_offer_59_1、jz_offer_59_2、jz_offer_60_1、jz_offer_61_1、jz_offer_62_1、jz_offer_63_1、jz_offer_64_1、jz_offer_65_1、jz_offer_66_1、jz_offer_67_1、jz_offer_68_1、jz_offer_68_2
 

assets/output/3324.md

@@ -0,0 +1,135 @@
+# [3324. 出现在屏幕上的字符串序列](https://leetcode.com/problems/find-the-sequence-of-strings-appeared-on-the-screen)
+
+🟠 <font color=#ffb800>Medium</font>&emsp; 🔗&ensp;[`LeetCode`](https://leetcode.com/problems/find-the-sequence-of-strings-appeared-on-the-screen)
+
+## 题目
+
+You are given a string `target`.
+
+Alice is going to type `target` on her computer using a special keyboard that
+has **only two** keys:
+
+  * Key 1 appends the character `"a"` to the string on the screen.
+  * Key 2 changes the **last** character of the string on the screen to its **next** character in the English alphabet. For example, `"c"` changes to `"d"` and `"z"` changes to `"a"`.
+
+**Note** that initially there is an _empty_ string `""` on the screen, so she
+can **only** press key 1.
+
+Return a list of _all_ strings that appear on the screen as Alice types
+`target`, in the order they appear, using the **minimum** key presses.
+
+
+
+**Example 1:**
+
+**Input:** target = "abc"
+
+**Output:** ["a","aa","ab","aba","abb","abc"]
+
+**Explanation:**
+
+The sequence of key presses done by Alice are:
+
+  * Press key 1, and the string on the screen becomes `"a"`.
+  * Press key 1, and the string on the screen becomes `"aa"`.
+  * Press key 2, and the string on the screen becomes `"ab"`.
+  * Press key 1, and the string on the screen becomes `"aba"`.
+  * Press key 2, and the string on the screen becomes `"abb"`.
+  * Press key 2, and the string on the screen becomes `"abc"`.
+
+**Example 2:**
+
+**Input:** target = "he"
+
+**Output:** ["a","b","c","d","e","f","g","h","ha","hb","hc","hd","he"]
+
+
+
+**Constraints:**
+
+  * `1 <= target.length <= 400`
+  * `target` consists only of lowercase English letters.
+
+
+## 题目大意
+
+给你一个字符串 `target`。
+
+Alice 将会使用一种特殊的键盘在她的电脑上输入 `target`，这个键盘**只有两个** 按键：
+
+  * 按键 1：在屏幕上的字符串后追加字符 `'a'`。
+  * 按键 2：将屏幕上字符串的 **最后一个** 字符更改为英文字母表中的 **下一个** 字符。例如，`'c'` 变为 `'d'`，`'z'` 变为 `'a'`。
+
+**注意** ，最初屏幕上是一个 _空_ 字符串 `""`，所以她**只能** 按按键 1。
+
+请你考虑按键次数 **最少** 的情况，按字符串出现顺序，返回 Alice 输入 `target` 时屏幕上出现的所有字符串列表。
+
+
+
+**示例 1：**
+
+**输入：** target = "abc"
+
+**输出：** ["a","aa","ab","aba","abb","abc"]
+
+**解释：**
+
+Alice 按键的顺序如下：
+
+  * 按下按键 1，屏幕上的字符串变为 `"a"`。
+  * 按下按键 1，屏幕上的字符串变为 `"aa"`。
+  * 按下按键 2，屏幕上的字符串变为 `"ab"`。
+  * 按下按键 1，屏幕上的字符串变为 `"aba"`。
+  * 按下按键 2，屏幕上的字符串变为 `"abb"`。
+  * 按下按键 2，屏幕上的字符串变为 `"abc"`。
+
+**示例 2：**
+
+**输入：** target = "he"
+
+**输出：** ["a","b","c","d","e","f","g","h","ha","hb","hc","hd","he"]
+
+
+
+**提示：**
+
+  * `1 <= target.length <= 400`
+  * `target` 仅由小写英文字母组成。
+
+
+## 解题思路
+
+#### 复杂度分析
+
+- **时间复杂度**：`O()`，
+- **空间复杂度**：`O()`，
+
+## 代码
+
+```javascript
+
+```
+
+## 相关题目
+
+<!-- prettier-ignore -->
+| 题号 | 标题 | 题解 | 标签 | 难度 |
+| :------: | :------ | :------: | :------ | :------ |
+| 500 | [键盘行](https://leetcode.com/problems/keyboard-row) |  |  [`数组`](/tag/array.md) [`哈希表`](/tag/hash-table.md) [`字符串`](/tag/string.md) | <font color=#15bd66>Easy</font> |
+
+<style>
+.blue {
+    background-color: #096dd9;
+    padding: 0.25rem 0.5rem;
+    margin: 0;
+    font-size: 0.85em;
+    border-radius: 3px;
+    color: white;
+    font-weight: 500;
+}
+table th:first-of-type { width: 10%; }
+table th:nth-of-type(2) { width: 35%; }
+table th:nth-of-type(3) { width: 10%; }
+table th:nth-of-type(4) { width: 35%; }
+table th:nth-of-type(5) { width: 10%; }
+</style>

assets/output/3325.md

@@ -0,0 +1,100 @@
+# [3325. 字符至少出现 K 次的子字符串 I](https://leetcode.com/problems/count-substrings-with-k-frequency-characters-i)
+
+🟠 <font color=#ffb800>Medium</font>&emsp; 🔗&ensp;[`LeetCode`](https://leetcode.com/problems/count-substrings-with-k-frequency-characters-i)
+
+## 题目
+
+Given a string `s` and an integer `k`, return the total number of substrings
+of `s` where **at least one** character appears **at least** `k` times.
+
+
+
+**Example 1:**
+
+**Input:** s = "abacb", k = 2
+
+**Output:** 4
+
+**Explanation:**
+
+The valid substrings are:
+
+  * `"aba"` (character `'a'` appears 2 times).
+  * `"abac"` (character `'a'` appears 2 times).
+  * `"abacb"` (character `'a'` appears 2 times).
+  * `"bacb"` (character `'b'` appears 2 times).
+
+**Example 2:**
+
+**Input:** s = "abcde", k = 1
+
+**Output:** 15
+
+**Explanation:**
+
+All substrings are valid because every character appears at least once.
+
+
+
+**Constraints:**
+
+  * `1 <= s.length <= 3000`
+  * `1 <= k <= s.length`
+  * `s` consists only of lowercase English letters.
+
+
+## 题目大意
+
+给你一个字符串 `s` 和一个整数 `k`，在 `s` 的所有子字符串中，请你统计并返回 **至少有一个** 字符 **至少出现** `k`
+次的子字符串总数。
+
+**子字符串** 是字符串中的一个连续、**非空** 的字符序列。
+
+
+
+**示例 1：**
+
+**输入：** s = "abacb", k = 2
+
+**输出：** 4
+
+**解释：**
+
+符合条件的子字符串如下：
+
+  * `"aba"`（字符 `'a'` 出现 2 次）。
+  * `"abac"`（字符 `'a'` 出现 2 次）。
+  * `"abacb"`（字符 `'a'` 出现 2 次）。
+  * `"bacb"`（字符 `'b'` 出现 2 次）。
+
+**示例 2：**
+
+**输入：** s = "abcde", k = 1
+
+**输出：** 15
+
+**解释：**
+
+所有子字符串都有效，因为每个字符至少出现一次。
+
+
+
+**提示：**
+
+  * `1 <= s.length <= 3000`
+  * `1 <= k <= s.length`
+  * `s` 仅由小写英文字母组成。
+
+
+## 解题思路
+
+#### 复杂度分析
+
+- **时间复杂度**：`O()`，
+- **空间复杂度**：`O()`，
+
+## 代码
+
+```javascript
+
+```