Add solution and test-cases for problem 2241

Author: 0xff-dev

leetcode/2201-2300/2241.Design-an-ATM-Machine/README.md

@@ -1,28 +1,45 @@
 # [2241.Design an ATM Machine][title]
 
-> [!WARNING|style:flat]
-> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
-
 ## Description
+There is an ATM machine that stores banknotes of `5` denominations: `20`, `50`, `100`, `200`, and `500` dollars. Initially the ATM is empty. The user can use the machine to deposit or withdraw any amount of money.
 
-**Example 1:**
+When withdrawing, the machine prioritizes using banknotes of **larger** values.
 
-```
-Input: a = "11", b = "1"
-Output: "100"
-```
+- For example, if you want to withdraw `$300` and there are `2` `$50` banknotes, `1` `$100` banknote, and `1` `$200` banknote, then the machine will use the `$100` and `$200` banknotes.
+- However, if you try to withdraw `$600` and there are `3` `$200` banknotes and `1` `$500` banknote, then the withdraw request will be rejected because the machine will first try to use the `$500` banknote and then be unable to use banknotes to complete the remaining `$100`. Note that the machine is **not** allowed to use the `$200` banknotes instead of the `$500` banknote.
 
-## 题意
-> ...
+Implement the ATM class:
 
-## 题解
+- `ATM()` Initializes the ATM object.
+- `void deposit(int[] banknotesCount)` Deposits new banknotes in the order `$20`, `$50`, `$100`, `$200`, and `$500`.
+- `int[] withdraw(int amount)` Returns an array of length `5` of the number of banknotes that will be handed to the user in the order `$20`, `$50`, `$100`, `$200`, and `$500`, and update the number of banknotes in the ATM after withdrawing. Returns `[-1]` if it is not possible (do **not** withdraw any banknotes in this case).
 
-### 思路1
-> ...
-Design an ATM Machine
-```go
-```
+**Example 1:**
 
+```
+Input
+["ATM", "deposit", "withdraw", "deposit", "withdraw", "withdraw"]
+[[], [[0,0,1,2,1]], [600], [[0,1,0,1,1]], [600], [550]]
+Output
+[null, null, [0,0,1,0,1], null, [-1], [0,1,0,0,1]]
+
+Explanation
+ATM atm = new ATM();
+atm.deposit([0,0,1,2,1]); // Deposits 1 $100 banknote, 2 $200 banknotes,
+                          // and 1 $500 banknote.
+atm.withdraw(600);        // Returns [0,0,1,0,1]. The machine uses 1 $100 banknote
+                          // and 1 $500 banknote. The banknotes left over in the
+                          // machine are [0,0,0,2,0].
+atm.deposit([0,1,0,1,1]); // Deposits 1 $50, $200, and $500 banknote.
+                          // The banknotes in the machine are now [0,1,0,3,1].
+atm.withdraw(600);        // Returns [-1]. The machine will try to use a $500 banknote
+                          // and then be unable to complete the remaining $100,
+                          // so the withdraw request will be rejected.
+                          // Since the request is rejected, the number of banknotes
+                          // in the machine is not modified.
+atm.withdraw(550);        // Returns [0,1,0,0,1]. The machine uses 1 $50 banknote
+                          // and 1 $500 banknote.
+```
 
 ## 结语
 

leetcode/2201-2300/2241.Design-an-ATM-Machine/Solution.go

@@ -1,5 +1,67 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+type ATM struct {
+	value [5]int
+	atm   [5]int
+}
+
+func Constructor() ATM {
+	return ATM{
+		value: [5]int{20, 50, 100, 200, 500},
+		atm:   [5]int{},
+	}
+}
+
+func (this *ATM) Deposit(banknotesCount []int) {
+	for i := range 5 {
+		this.atm[i] += banknotesCount[i]
+	}
+}
+
+func (this *ATM) Withdraw(amount int) []int {
+	index := 4
+	ret := make([]int, 5)
+	for ; index >= 0; index-- {
+		if this.atm[index] != 0 {
+			break
+		}
+	}
+	if index == -1 {
+		return []int{-1}
+	}
+	source := this.atm
+	for ; index >= 0 && amount > 0; index-- {
+		if this.atm[index] > 0 {
+			c := amount / this.value[index]
+			use := min(c, this.atm[index])
+			amount -= use * this.value[index]
+			this.atm[index] = max(0, this.atm[index]-use)
+			ret[index] = use
+		}
+	}
+	if amount > 0 {
+		// 不要见
+		this.atm = source
+		return []int{-1}
+	}
+	return ret
+}
+
+type op struct {
+	name           byte
+	banknotesCount []int
+	amount         int
+}
+
+func Solution(opts []op) [][]int {
+	var ret [][]int
+	atm := Constructor()
+	for _, o := range opts {
+		if o.name == 'd' {
+			atm.Deposit(o.banknotesCount)
+			continue
+		}
+		ret = append(ret, atm.Withdraw(o.amount))
+	}
+	return ret
 }

leetcode/2201-2300/2241.Design-an-ATM-Machine/Solution_test.go

@@ -10,12 +10,16 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
-		expect bool
+		inputs []op
+		expect [][]int
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", []op{
+			{'d', []int{0, 0, 1, 2, 1}, 0},
+			{'w', []int{}, 600},
+			{'d', []int{0, 1, 0, 1, 1}, 0},
+			{'w', []int{}, 600},
+			{'w', []int{}, 550},
+		}, [][]int{{0, 0, 1, 0, 1}, {-1}, {0, 1, 0, 0, 1}}},
 	}
 
 	//	开始测试
@@ -30,10 +34,10 @@ func TestSolution(t *testing.T) {
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }