Fix colored view display when all list items are removed

When comparing two lists where all items are removed (t2 becomes an empty list),
the colored view would display an empty list [] instead of showing the removed
items in red.

The bug occurred because `_colorize_json()` returned '[]' immediately if the
list was empty, without checking for items that were removed and should be
displayed.

Fix: Check for removed items before returning empty list representation.

Added tests:
- test_colored_view_list_all_items_removed
- test_colored_compact_view_list_all_items_removed

Author: yannrouillard

deepdiff/colored_view.py

@@ -109,9 +109,10 @@ def _colorize_json(self, obj: Any, path: str = 'root', indent: int = 0) -> str:
             return '{\n' + ',\n'.join(items) + f'\n{current_indent}' + '}'
 
         elif isinstance(obj, (list, tuple)):
-            if not obj:
-                return '[]'
             removed_map = self._get_path_removed(path)
+            if not obj and not removed_map:
+                return '[]'
+
             for index in removed_map:
                 self._colorize_skip_paths.add(f"{path}[{index}]")
 

tests/test_colored_view.py

@@ -134,6 +134,36 @@ def test_colored_view_list_additions():
     assert result == expected
 
 
+def test_colored_view_list_all_items_removed():
+    """Test that all removed items are displayed when list becomes empty."""
+    t1 = [2, 4]
+    t2 = []
+
+    diff = DeepDiff(t1, t2, view=COLORED_VIEW)
+    result = str(diff)
+
+    expected = f'''[
+  {RED}2{RESET},
+  {RED}4{RESET}
+]'''
+    assert result == expected
+
+
+def test_colored_compact_view_list_all_items_removed():
+    """Test that all removed items are displayed when list becomes empty with compact view."""
+    t1 = [2, 4]
+    t2 = []
+
+    diff = DeepDiff(t1, t2, view=COLORED_COMPACT_VIEW)
+    result = str(diff)
+
+    expected = f'''[
+  {RED}2{RESET},
+  {RED}4{RESET}
+]'''
+    assert result == expected
+
+
 def test_colored_view_list_changes_deletions():
     t1 = [1, 5, 7, 3, 6]
     t2 = [1, 2, 3, 4]