Add solution and test-cases for problem 2654

leetcode/2601-2700/2654.Minimum-Number-of-Operations-to-Make-All-Array-Elements-Equal-to-1/README.md

@@ -0,0 +1,37 @@
+# [2654.Minimum Number of Operations to Make All Array Elements Equal to 1][title]
+
+## Description
+You are given a **0-indexed** array `nums` consisiting of **positive** integers. You can do the following operation on the array **any** number of times:
+
+- Select an index `i` such that `0 <= i < n - 1` and replace either of `nums[i]` or `nums[i+1]` with their gcd value.
+
+Return the **minimum** number of operations to make all elements of `nums` equal to `1`. If it is impossible, return `-1`.
+
+The gcd of two integers is the greatest common divisor of the two integers.
+
+**Example 1:**
+
+```
+Input: nums = [2,6,3,4]
+Output: 4
+Explanation: We can do the following operations:
+- Choose index i = 2 and replace nums[2] with gcd(3,4) = 1. Now we have nums = [2,6,1,4].
+- Choose index i = 1 and replace nums[1] with gcd(6,1) = 1. Now we have nums = [2,1,1,4].
+- Choose index i = 0 and replace nums[0] with gcd(2,1) = 1. Now we have nums = [1,1,1,4].
+- Choose index i = 2 and replace nums[3] with gcd(1,4) = 1. Now we have nums = [1,1,1,1].
+```
+
+**Example 2:**
+
+```
+Input: nums = [2,10,6,14]
+Output: -1
+Explanation: It can be shown that it is impossible to make all the elements equal to 1.
+```
+
+## 结语
+
+如果你同我一样热爱数据结构、算法、LeetCode，可以关注我 GitHub 上的 LeetCode 题解：[awesome-golang-algorithm][me]
+
+[title]: https://leetcode.com/problems/minimum-number-of-operations-to-make-all-array-elements-equal-to-1/
+[me]: https://github.com/kylesliu/awesome-golang-algorithm

leetcode/2601-2700/2654.Minimum-Number-of-Operations-to-Make-All-Array-Elements-Equal-to-1/Solution.go

@@ -1,5 +1,41 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+func gcd2654(a, b int) int {
+	for b != 0 {
+		a, b = b, a%b
+	}
+	return a
+}
+
+func Solution(nums []int) int {
+	l := len(nums)
+	ones := 0
+	// 有1就是直接响四周扩散就可以
+	for _, n := range nums {
+		if n == 1 {
+			ones++
+		}
+	}
+	if ones > 0 {
+		return l - ones
+	}
+
+	// 没有，就需要看否构建出1
+	minLenArrayWithOne := l + 1
+	// 2, 2, 3, 4, 5
+	for i := 0; i < l; i++ {
+		gcdNum := nums[i]
+		for j := i + 1; j < l; j++ {
+			gcdNum = gcd2654(gcdNum, nums[j])
+			if gcdNum == 1 {
+				minLenArrayWithOne = min(minLenArrayWithOne, j-i+1)
+				break
+			}
+		}
+	}
+	if minLenArrayWithOne == l+1 {
+		return -1
+	}
+	// 构建minLenArrayWithOne里面的1，需要-1次，然后扩散到整个数组
+	return minLenArrayWithOne - 1 + l - 1
 }

leetcode/2601-2700/2654.Minimum-Number-of-Operations-to-Make-All-Array-Elements-Equal-to-1/Solution_test.go

@@ -10,12 +10,11 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
-		expect bool
+		inputs []int
+		expect int
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", []int{2, 6, 3, 4}, 4},
+		{"TestCase2", []int{2, 10, 6, 14}, -1},
 	}
 
 	//	开始测试
@@ -30,10 +29,10 @@ func TestSolution(t *testing.T) {
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }