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37 changes: 37 additions & 0 deletions 862. Shortest Subarray with Sum at Least K
Original file line number Diff line number Diff line change
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class Solution {
public:
int shortestSubarray(vector<int>& nums, int k) {
int n=nums.size();

// find the prefix sum of the given array nums -:
// Size is n+1 to handle subarrays starting from index 0
vector<long long>prefixSum(n+1,0);

// Calculating prefix sums
for(int i=1; i<=n; i++){
prefixSum[i]=prefixSum[i-1]+nums[i-1];
}

// Make a deque (doubly-ended queue -: which allows us to add/remove ele.s
// from both front/end side.
deque<int>candiIdx;

int len=INT_MAX;

for(int i=0; i<=n; i++){
// Remove candidates from front of deque where subarray sum meets target sum
while(!candiIdx.empty() && prefixSum[i]-prefixSum[candiIdx.front()]>=k){
len=min(len,i-candiIdx.front());
candiIdx.pop_front();
}
// Maintain monotonicity by removing indices with larger prefix sums
while(!candiIdx.empty() && prefixSum[i]<=prefixSum[candiIdx.back()]) {
candiIdx.pop_back();
}
// Add current index to candidates
candiIdx.push_back(i);
}
// Return -1 if no valid subarray found
return len == INT_MAX ? -1 : len;
}
};
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