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NW6 | Nazanin_Saedi| Module-JS1 | WEEK4 #182
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Ara225
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Dec 2, 2023
Ara225
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Ara225
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Some bits undone - please keep plodding on - its all looking good
| // Additional logic to handle consecutive occurrences | ||
| // For example, if char is 'a' and str is 'aaaaa', | ||
| // we want to count this as one occurrence of 'a'. | ||
| // So, we can skip consecutive occurrences by incrementing i until a different character is encountered. |
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This works but is not what the question asked for I'm afraid - please read the instructions again and tweak it
| * Function to get the ordinal representation of a number. | ||
| * @param {number} n - The input number. | ||
| * @returns {string} - The ordinal representation of the input number. | ||
| */ |
| // If it is divisible, the function returns false, indicating that the number is not prime. | ||
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| // Check for divisibility from 2 to the square root of the number | ||
| for (let i = 2; i <= Math.sqrt(num); i++) { |
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This works, but it is quite complicated - are you confident in your understanding?
| // Defines a function named isPasswordValid that takes a parameter password. | ||
| function isPasswordValid(password) { | ||
| // Step 1: Check if the password has at least 5 characters | ||
| if (password.length < 5) { |
| // When the repeat function is called with these inputs, | ||
| // Then it should throw an error or return an appropriate error message, as negative counts are not valid. | ||
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| //Defines a function named repeat that takes two parameters, str and count: |
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This is a really well formatted and streamlined solution, I like it a lot :)
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I try explain line by line . That way helps me understand each line and when I back to code I understand what I did .
please put review for me .